Transformation Of Graph Dse Exercise !!install!! May 2026
Transformation of Graphs
In the HKDSE Mathematics curriculum, is a critical topic frequently appearing in Paper 1 (Section A and B) and Paper 2 (Multiple Choice). It involves changing a parent function
Solution:
This is a classic DSE trap.
Given ( y = f(x) ) passes through ( A(2, 3) ), ( B(4, 0) ), ( C(6, 5) ). The graph is transformed to ( y = \frac12 f(x+2) - 1 ). Find the new coordinates of A, B, C. transformation of graph dse exercise
| New equation | Meaning | |--------------|---------| | (y = f(x-a) + b) | Right a, up b | | (y = -f(x)) | Reflect in x-axis | | (y = f(-x)) | Reflect in y-axis | | (y = k f(x)) | Vertical stretch (k>1) / compress (0<k<1) | | (y = f(ax)) | Horizontal compress (a>1) / stretch (0<a<1) | | (y = f(ax + b)) | First factor: (a(x + b/a)) → compress by (1/a), then shift left (b/a) | Wrong: ( y = f(x+3) ) moves right
Watch for :
-axis don't move. During a horizontal stretch, points on the -axis stay put. flips it upside down. mirrors it like a book cover. 📝 Common Trap: The Coefficient of In the DSE, they might give you . Do not just shift right by 4. You must factor it first: Overview
Solution
- Wrong: ( y = f(x+3) ) moves right.
- Correct: ( y = f(x+3) ) moves left (because you need ( x ) to be 3 less to get same output).
Overview
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